Calculate the volume of hydrogen released by the interaction of 27 g of aluminum with hydrochloric acid.

Aluminum reacts violently with hydrochloric acid. At the same time, the salt of aluminum chloride is synthesized and bubbles of hydrogen gas are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s calculate the chemical amount of aluminum. For this purpose, we divide its weight by the molar weight of the substance.

M Al = 27 grams / mol;

N Al = 27/27 = 1 mol;

This will synthesize the same amount of salt.

The chemical amount of released hydrogen will be: 1 x 3/2 = 1.5 mol

Let’s define its volume.

To do this, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 1.5 x 22.4 = 33.6 liters;