Calculate the volume of hydrogen released by the interaction of 64 g of potassium with sulfuric acid.

univerkov | December 9, 2020 | education

K + H2SO4 -> K2SO4 + H2
m (K) = 64g n (K) = m / M = 64g / 39g / mol = 1.64 mol n (K) = n (H2) = 1.64 mol V (H2) = Vm * n = 22.4 l / mol * 1.64 mol ~ 36.76 l
Answer: 36.76L

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