Calculate the volume of hydrogen released by the reaction of 30 g of zinc with 200 ml of 20% hydrochloric

Calculate the volume of hydrogen released by the reaction of 30 g of zinc with 200 ml of 20% hydrochloric acid solution (p = 1.1 g / ml)

Metallic zinc “dissolves” in hydrochloric acid, the reaction proceeds in accordance with the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s determine the chemical amount of zinc. To do this, we divide its weight by the molar weight of elemental zinc.

M Zn = 65 grams / mol;

N Zn = 30/65 = 0.4615 mol;

Let’s calculate the molar amount of hydrogen chloride. For this purpose, we divide its mass by the molar mass of this elemental acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 200 x 0.2 x 1.1 / 36.5 = 1.2 mol;

Acid taken in excess

0.4615 x 2 = 0.923 mol of acid will react with 0.4615 mol of metal, while 0.4615 mol of hydrogen will be released.

Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling the space of 22.4 liters).

V H2 = 0.4615 x 22.4 = 10.34 liters;