Calculate the volume of hydrogen released during the interaction of zinc weighing 13g with sulfuric acid weighing 16g.

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of sulfuric acid and zinc.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 16/98 = 0.163 mol;

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

During the reaction, 0.163 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 0.163 x 22.4 = 3.651 liters;