Calculate the volume of hydrogen released during the interaction of zinc weighing

Calculate the volume of hydrogen released during the interaction of zinc weighing 13 g and a solution containing 30 g of sulfuric acid.

1. Let’s compose the equality of chemical interaction:

Zn + H2SO4 = ZnSO4 + H2.

2. Let’s calculate the chemical number of zinc and sulfuric acid:

n (Zn) = m (Zn) / M (Zn) = 13 g / 65 g / mol = 0.2 mol.

n (H2SO4) = m (H2SO4) / M (H2SO4) = 30 g / 98g / mol = 0.306 mol.

3. Using the equality of chemical interaction, we find the number of moles and, as a result, the volume of hydrogen (Vm is the molar volume equal to 22.4 l / mol):

! Zn is in short supply.

n (H2) = n (Zn) = 0.2 mol.

V (H2) = n (H2) * Vm = 0.2 mol * 22.4 L / mol = 4.48 L.

Result: V (H2) = 4.48 liters.