Calculate the volume of hydrogen released during the reaction of 20 g of calcium and 70 g

Calculate the volume of hydrogen released during the reaction of 20 g of calcium and 70 g of a chloride acid solution with a mass fraction of HCL of 20%.

The reaction of calcium with hydrochloric acid is described by the following chemical reaction equation:

Ca + 2HCl = CaCl2 + H2;

For a reaction with one mole of calcium, two moles of hydrochloric acid are needed.

Let’s find the molar amounts of calcium and hydrogen chloride.

The molar mass of calcium is 40 grams / mol;

Amount of calcium substance:

N Ca = 20/40 = 0.5 mol;

70 grams of a 20% hydrochloric acid solution contains 70 x 0.2 = 14 grams of hydrogen chloride.

The amount of hydrogen chloride:

N HCl = 14 / (35.5 + 1) = 0.384 mol;

The entire volume of hydrogen chloride and 0.384 / 2 = 0.192 mol of calcium will enter into the reaction.

The amount of released hydrogen will be 0.192 mol;

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let us determine the volume of 0.192 mol of hydrogen:

V H2 = 0.192 x 22.4 = 4.3008 liters;