Calculate the volume of hydrogen released when 48 g of magnesium reacts with sulfuric acid

The active element, metallic magnesium, when it enters sulfuric acid, dissolves in it with the release of bubbles of hydrogen gas. The chemical process is described by the following equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Find the molar amount of magnesium, which is expressed in moles.

To do this, we divide its mass by the weight of 1 mole of metallic magnesium (its molar weight).

M Mg = 24 grams per mole;

N Mg = 48/24 = 2 mol;

The same equivalent amount of hydrogen will be synthesized.

Determine the volume of hydrogen gas.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.40 liters).

V H2 = 2 x 22.4 = 44.8 liters;