Calculate the volume of hydrogen. Released when aluminum is dissolved in 27 g, 40% hydrochloric acid solution.

Metallic aluminum interacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and bubbles of hydrogen gas are released. The reaction is described by the following equation.
Al + 3HCl = AlCl3 + 3/2 H2;
Let’s calculate the chemical amount of hydrochloric acid. For this purpose, we divide its weight by the molar weight of the acid.
M HCl = 1 + 35.5 = 36.5 grams / mol;
N HCl = 27 x 0.4 / 36.5 = 0.2959 mol;
The chemical amount of released hydrogen will be 2 times less: 0.2959 / 2 = 0.1479 mol
Let’s define its volume.
To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).
V H2 = 0.1479 x 22.4 = 3.314 liters;
The weight of hydrogen will be:
M H2 = 2 grams / mol;
m H2 = 2 x 0.1479 = 0.2959 grams;



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