Calculate the volume of hydrogen released when dissolving magnesium, weighing 120 g, containing 2%

Calculate the volume of hydrogen released when dissolving magnesium, weighing 120 g, containing 2% impurities in hydrochloric acid

Magnesium reacts with hydrochloric acid to release hydrogen and form magnesium chloride:

Mg + 2HCl = MgCl2 + H2;

In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 120 x 0.98 / 24 = 4.9 mol;

The same amount of hydrogen will be synthesized.

Let’s calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 4.9 x 22.4 = 109.76 liters;