Calculate the volume of hydrogen released when interacting with sulfuric acid with 4.8 g of magnesium. Find the volume of hydrogen.

univerkov | December 3, 2020 | education

Given:
m (Mg) = 4.8 g
Find: V (H2)
Decision:
Let’s write down the reaction
H2SO4 + Mg = MgSO4 + H2
M (Mg) = 24 g / mol
Find the volume of hydrogen through the proportion
m / M = V / Vm
4.8 / 24 = x / 22.4
x = 4.48 l

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