Calculate the volume of hydrogen required for the reduction of 20L ethanol.

1. Let’s compose the equation of the chemical reaction:

CH3CHO + H2 = C2H5OH.

2. Find the chemical amount of ethanal (Vm – molar volume, constant equal to 22.4 l / mol):

n (CH3CHO) = V (CH3CHO) / Vm = 20 L / 22.4 L / mol = 0.89 mol.

3. According to the reaction equation, we find the chemical amount of hydrogen, and then its volume:

n (H2) = n (CH3CHO) = 0.89 mol.

V (H2) = n (H2) * Vm = 0.89 mol * 22.4 L / mol = 20 L.

Answer: V (H2) = 20 liters.



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