Calculate the volume of hydrogen required to convert 2 moles of butene to butane

In accordance with the condition of the problem, we write down the equation of the process:

C4H8 + H2 = C4H10 – hydrogenation, butane was formed;

Let’s set the amount of the original substance:
Y (C4H8) = 2 mol;

Y (H2) = 2 mol since the amount of substances is 1 mol.

We find the volume of H2:
V (H2) = 2 * 22.4 = 44.8 L

Answer: you need 44.8 liters of hydrogen