Calculate the volume of hydrogen required to obtain 30 g of water, when interacting with oxygen (O2).

The combustion reaction of hydrogen is described by the following chemical equation:

2H2 + O2 = 2H2O;

To obtain one mole of water, one mole of hydrogen is needed.

Let’s determine the amount of substance in 30 grams of water.

Its molar mass is 16 + 1 +1 = 18 grams / mol.

N H2O = 30/18 = 1.6667 mol;

The required amount of hydrogen will be the same amount:

N H2 = 1.6667 x 1 = 1.6667 mol;

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

1.6667 mol of hydrogen will occupy the volume:

V H2 = 1.6667 x 22.4 = 37.3341 liters;

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