Calculate the volume of hydrogen sulfide that can be obtained during the hydrolysis
May 30, 2021 | education
| Calculate the volume of hydrogen sulfide that can be obtained during the hydrolysis of technical aluminum sulfide weighing 60 g, which contains 12.5% impurities.
Запишем уравнение реакции гидролиза сульфида алюминия водой.
Al2S3 + 6H2O = 2Al(OH)3 + 3H2S
Al2S3 – технический, содержит примеси (12,5 %). Найдем массу чистого сульфида алюминия (100% – 12,5% = 87,5%).
m(Al2S3) = 60*87,5/100 = 52,5 г.
Рассчитаем количество моль Al2S3.
n(Al2S3) = m/M = 52,5/150,2 = 0,35 моль
Составим пропорцию:
1 моль Al2S3 – 3 моль H2S
0,35 моль Al2S3 – x моль H2S
x (H2S) = 1,05 моль
Вычислим объем сероводорода, домножив количество моль на молярный объем газа при нормальных условиях.
V(H2S) = n*Vm = 1,05*22,4 = 23,52 л.
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