# Calculate the volume of hydrogen that can be obtained as a result of the interaction of aluminum

**Calculate the volume of hydrogen that can be obtained as a result of the interaction of aluminum weighing 28 g with hydrochloric acid.**

Aluminum reacts violently with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

Let’s determine the chemical amount of aluminum. To do this, we divide its weight by the molar weight of the substance.

M Al = 27 grams / mol;

N Al = 28/27 = 1.037 mol;

The chemical amount of released hydrogen will be: 1.037 x 3/2 = 1.555 mol

Let’s find its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling the space with a volume of 22.4 liters).

V H2 = 1.555 x 22.4 = 34.844 liters;