Calculate the volume of hydrogen that can be obtained by reacting 60 g Mg with hydrochloric acid

Calculate the volume of hydrogen that can be obtained by reacting 60 g Mg with hydrochloric acid if the yield of the reaction product is 95%.

Given:
m (Mg) = 60 g
ω out. = 95%

To find:
V practical. (H2) -?

Decision:
1) Mg + 2HCl => MgCl2 + H2 ↑;
2) n (Mg) = m (Mg) / Mr (Mg) = 60/24 = 2.5 mol;
3) n (H2) = n (Mg) = 2.5 mol;
4) V theor. (H2) = n (H2) * Vm = 2.5 * 22.4 = 56 liters;
5) V practical. (H2) = ω out. * V theor. (H2) / 100% = 95% * 56/100% = 53.2 liters.

Answer: The volume of H2 is 53.2 liters.