Calculate the volume of hydrogen that can be obtained if you take 1 mol of methyl alcohol

Calculate the volume of hydrogen that can be obtained if you take 1 mol of methyl alcohol and 1.5 mol of metallic potassium for the reaction.

Let’s write down the reaction scheme and arrange the coefficients:
2CH3OH + 2K = 2CH3OK + H2
It can be seen from the reaction equation that 1 mol of potassium is required for 1 mol of methanol. According to the condition of the problem, it can be seen that potassium is in excess. All calculations are based on insufficient reagent, that is, methanol. Hence, it turns out that from 1 mol of methanol, n (H2) = 0.5 mol of hydrogen is formed. Let’s calculate its volume:
V (H2) = Vm * n (H2), where Vm = 22.4 l / mol – molar volume, is the same for all gases under normal conditions.
V (H2) = 0.5 * 22.4 = 11.2 L