Calculate the volume of hydrogen that is formed by reacting with hydrochloric acid 101.25 kg

Calculate the volume of hydrogen that is formed by reacting with hydrochloric acid 101.25 kg of aluminum containing 20% impurities.

Given:
m tech. (Al) = 101.25 kg = 101250 g
ω approx. = 20%

To find:
V (H2) -?

Solution:
1) 6HCl + 2Al => 2AlCl3 + 3H2 ↑;
2) M (Al) = Mr (Al) = Ar (Al) = 27 g / mol;
3) ω (Al) = 100% – ω approx. = 100% – 20% = 80%;
4) m clean. (Al) = ω (Al) * m tech. (Al) / 100% = 80% * 101250/100% = 81000 g;
5) n (Al) = m pure. (Al) / M (Al) = 81000/27 = 3000 mol;
6) n (H2) = n (Al) * 3/2 = 3000 * 3/2 = 4500 mol;
7) V (H2) = n (H2) * Vm = 4500 * 22.4 = 100800 hp

Answer: The volume of H2 is 100,800 liters.