Calculate the volume of hydrogen that is formed by the interaction of 0.5 mol of zinc with an excess of hydrochloric
| September 24, 2021 | education
Calculate the volume of hydrogen that is formed by the interaction of 0.5 mol of zinc with an excess of hydrochloric acid according to the reaction equation: Zn + 2HCl = ZnCl2 + H2
Zn + 2HCl = ZnCl2 + H2.
The amount of released hydrogen is the same as the reacted zinc, 0.5 mol. Then the volume H2 at n.o. is equal to 22.4 l / mol * 0.5 mol = 11.2 l.
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