Calculate the volume of hydrogen that is formed by the interaction of 1.5 mol of aluminum with hydrochloric acid.

Calculate the volume of hydrogen that is formed by the interaction of 1.5 mol of aluminum with hydrochloric acid. How much hydrochloric acid is required for this reaction?

Aluminum reacts with hydrochloric acid. In this case, an aluminum chloride salt is formed and elemental hydrogen is released. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

N Al = 1.5 mol;

The reaction will require 1.5 x 3 = 4.5 mol of hydrochloric acid.

The chemical amount of released hydrogen will be: 1.5 x 3/2 = 2.25 mol

Let’s find its volume.

For this purpose, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 2.25 x 22.4 = 50.4 liters;