Calculate the volume of hydrogen that is formed by the interaction of 48 g of magnesium with hydrochloric acid.

1. Let’s compose the reaction equation and arrange the coefficients.

Mg + 2HCl = MgCl2 + H2

2. Let us find the amount of magnesium substance by the formula v = m / Mr, where m is the mass of the substance, v is the amount of the substance, Mr is the molecular mass.

Mr (Mg) = 24.3 g / mol

v (Mg) = 48 / 24.3 = 1.975 mol

3. Magnesium is in a ratio with hydrogen as 1: 1, which means that the amount of magnesium will be equal to the amount of hydrogen.

v (Mg) = v (H2) = 1.975 mol

4. Let us find the volume of hydrogen by the formula V = v * 22.4, where V is the volume of a substance, 22.4 l / mol is the molar volume of gases.

V (H2) = 1.975 * 22.4 = 44.24 L