Calculate the volume of hydrogen that is formed by the interaction of 5.4 grams of aluminum with

Calculate the volume of hydrogen that is formed by the interaction of 5.4 grams of aluminum with an excess of hydrochloric acid.

1. We make a chemical equation, not forgetting to put down the coefficients:

4Al + 6HCl = 2AlCl3 + 3H2.

2. Find the amount of aluminum substance:

n (Al) = m / M = 5.4g / 27g / mol = 0.2 mol.

3. Find the amount of substance hydrogen:

n (H2) / n (Al) = 3/4, therefore n (H2) = 3 * 0.2 / 4 = 0.15 mol.

4. Find the volume of hydrogen:

V (H2) = n * Vm = 0.15 mol * 22.4 l / mol = 3.36 l.

Answer: V (H2) = 3.36 liters.