Calculate the volume of hydrogen that is formed by the interaction of lithium weighing 3.4 g

Calculate the volume of hydrogen that is formed by the interaction of lithium weighing 3.4 g with an excess of 96% ethanol.

1. The interaction of lithium with ethanol proceeds according to the equation:

2C2H5OH + 2Li → 2C2H5OLi + H2 ↑;

2.Calculate the chemical amount of lithium:

n (Li) = m (Li): M (Li) = 3.4: 7 = 0.4857 mol;

3. Determine the amount of released hydrogen:

n (H2) = n (Li): 2 = 0.4857: 2 = 0.24285 mol;

4.calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.24285 * 22.4 = 5.44 liters.

Answer: 5.44 liters.