Calculate the volume of hydrogen that is formed by treating 56 g of iron containing 5%

Calculate the volume of hydrogen that is formed by treating 56 g of iron containing 5% impurities with a sufficient amount of hydrochloric acid.

The reaction of iron with hydrochloric acid is described by the following chemical reaction equation:

Fe + 2HCl = FeCl2 + H2;

When one mole of iron reacts, one mole of hydrogen is formed.

Let’s determine the amount of substance in 56 grams of iron containing 5% impurities.

The mass of pure iron will be:

m Fe = 56 x 0.95 = 58.9 grams;

Let’s determine the amount of substance in this mass of iron. Its molar mass is 56 grams / mol.

N Fe = 58.9 / 56 = 1.052 mol;

The same amount of moles of hydrogen will be formed.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Determine the volume of hydrogen:

V H2 = 1.052 x 22.4 = 23.5648 liters;