Calculate the volume of hydrogen that will be released as a result of the interaction

Calculate the volume of hydrogen that will be released as a result of the interaction of sodium with a mass of 2.4 with acetic acid.

Let’s implement the solution:
1. Let’s write down the reaction equation:
2СН3СООН + 2Na = 2CH3COONa + H2 – substitution reaction, sodium acetate and hydrogen were obtained;
2. Let’s calculate the molar masses of substances:
M (Na) = 22.9 g / mol;
M (H2) = 2 g / mol;
3. Determine the number of moles of sodium, if its mass is known:
Y (Na) = m / M = 2.4 / 22.9 = 0.1 mol;
4. We make up the proportion:
0.1 mol (Na) – X mol (H2);
-2 mol – 1 mol from here, X mol (H2) = 0.1 * 1/2 = 0.05 mol;
5. Let’s calculate the volume of hydrogen, applying Avogadro’s law:
V (H2) = 0.05 * 22.4 = 1.12 liters.
Answer: during the reaction, hydrogen is released with a volume of 1.12 liters.



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