Calculate the volume of hydrogen that will be released as a result of the interaction of 19.5 g of zinc with a solution of H2TeO4.
1. Let’s compose the equation of interaction of telluric acid with zinc:
Zn + H2TeO4 = ZnTeO4 + H2 ↑.
2. Calculate the chemical amount of zinc reacted:
n (Zn) = m (Zn): M (Zn) = 19.5: 65 = 0.3 mol.
3. Determine the amount of released hydrogen:
n (H2) = n (Zn) = 0.3 mol.
4. Let’s calculate the volume of hydrogen:
V (H2) = n (H2) * Vm = 0.3 * 22.4 = 6.72 liters.
Answer: 6.72 liters.
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