Calculate the volume of hydrogen that will be released as a result of the interaction of 45.5 g

Calculate the volume of hydrogen that will be released as a result of the interaction of 45.5 g of zinc with a solution of H2Se.

1. Reaction equation: Zn + H2Se = ZnSe + H2.
2. According to the table. The periodic molar mass of Zn is 65.4 g / mol.
3. Let us find the number of moles of zinc, for this we divide the mass of 45.5 g by the molar mass, we get 0.7 mol.
4. Since when 1 mole of Zn enters the reaction, 1 mole of H2 is formed, the amount of Zn is equal to the amount of H2 and is equal to 0.7 mole.
5. To find the volume of H2, the amount (0.7 mol) is multiplied by the molar volume (22.4 l / mol), we get 15.68 l.