Calculate the volume of hydrogen that will be released as a result of the substitution

Calculate the volume of hydrogen that will be released as a result of the substitution reaction between magnesium and 50 g sulfuric acid solution.

Given:
m (H2SO4) = 50 g
To find:
V (H2)
Decision:
H2SO4 + Mg = MgSO4 + H2
n (H2SO4) = m / M = 50 g / 98 g / mol = 0.51 mol
n (H2SO4): n (H2) = 1: 1
n (H2) = 0.51 mol
V (H2) = n * Vm = 0.51 mol * 22.4 L / mol = 11.42 L
Answer: 11.42 L