Calculate the volume of hydrogen that will be released upon complete dissolution of magnesium

Calculate the volume of hydrogen that will be released upon complete dissolution of magnesium weighing 48,000 g in hydrochloric acid.

Metallic magnesium dissolves in hydrochloric acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2HCl = MgCl2 + H2 ↑;

Let’s calculate the chemical amount of a substance of metallic magnesium.

To do this, we divide this weight by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

N Mg = 48,000/24 = 2,000 mol;

The same amount of hydrogen gas will be produced.

Let’s determine the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 2,000 x 22.4 = 44,800 liters = 44.8 m3;



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