Calculate the volume of hydrogen that will be released when 120 g of magnesium containing 2.5

Calculate the volume of hydrogen that will be released when 120 g of magnesium containing 2.5 impurities are dissolved in hydrochloric acid.

The active element metallic magnesium, when it gets into hydrochloric acid, dissolves in it. The chemical process is described by the following equation:

Mg + 2HCl = MgCl2 + H2 ↑;

Let us determine the chemical amount of the elementary magnesium substance that has entered into chemical interaction.

For this purpose, we divide its mass by the weight of 1 mole of metallic magnesium (its molar weight).

M Mg = 24 grams / mol;

N Mg = 120 x (1 – 0.025) / 24 = 4.875 mol;

The same amount of hydrogen gas will be synthesized.

Let’s find the volume of this synthesized hydrogen.

To do this, multiply the amount of hydrogen gas substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters). The product of these two values ​​will be equal to the gas volume.

V H2 = 4.875 x 22.4 = 109.2 liters;