Calculate the volume of hydrogen that will be released when 130 g of zinc reacts

Calculate the volume of hydrogen that will be released when 130 g of zinc reacts with hydrochloric acid. How much chlorine is required to obtain 80 g of bromine from potassium bromide?

A. Zinc dissolves in hydrochloric acid, the reaction is described by the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s find the molar amount of zinc. To do this, we divide its weight by the molar weight of elemental zinc.

M Zn = 65 grams / mol;

N Zn = 130/65 = 2 mol;

The same amount of hydrogen will be released.

Let’s define the volume that it occupies.

To this end, we multiply the amount of substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters) ..

V H2 = 2 x 22.4 = 44.8 liters;

B. The reaction for producing bromine is described by the following equation:

Cl2 + KBr = KCl + Br2;

The amounts of chlorine and bromine are equal.

Let’s calculate the amount of bromine.

M Br2 = 80 x 2 = 160 grams / mol;

N Br2 = 80/160 = 0.5 mol;

Let’s calculate the volume of the same amount of chlorine.

N Cl2 = 0.5 mol;

V Cl2 = 0.5 x 22.4 = 11.2 liters;