Calculate the volume of hydrogen that will be released when 20 g of calcium interacts with nitric acid.

The equation for the interaction of calcium with nitric acid:
Ca + 2HNO3 = Ca (NO3) 2 + H2.
1) Determine the molar mass of calcium according to the periodic table: 40.
2) Find the amount of calcium. For this, the mass of calcium is divided by its molar mass: 20/40 = 0.5 mol.
3) Consider the reaction equation. One mole of calcium accounts for one mole of hydrogen. Thus, the amount of hydrogen substance is 0.5 mol.
4) Find the volume of hydrogen. To do this, we multiply the amount of hydrogen substance by its molar volume: 0.5 * 22.4 = 11.2 liters – the answer.



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