Calculate the volume of hydrogen that will be released when 49 g of sulfuric acid (H2SO4) reacts with zinc.

Metallic zinc interacts with sulfuric acid according to the following equation:

Zn + H2SO4 → ZnSO4 + H2;

The molar amount of hydrogen is equal to the amount of sulfuric acid reacted.

Let’s calculate the chemical amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 49/98 = 0.5 mol;

With this amount of zinc and acid, it is possible to obtain 0.5 mol of hydrogen.

Let’s calculate the volume of 0.5 mol of hydrogen.

V H2 = 22.4 x 0.5 = 11.2 liters;