Calculate the volume of hydrogen that will be released when 8 g of magnesium interacts with 60 g of acetic acid.

Given:
m (Mg) = 8 g

To find:
V (H2) -?

1) Write the reaction equation:
Mg + 2CH3COOH => Mg (CH3COO) 2 + H2;
2) Calculate the amount of Mg substance:
n (Mg) = m (Mg) / M (Mg) = 8/24 = 0.33 mol;
3) Determine the amount of substance H2:
n (H2) = n (Mg) = 0.33 mol;
4) Calculate the volume of H2 (under normal conditions):
V (H2) = n (H2) * Vm = 0.33 * 22.4 = 7.39 liters.

Answer: The volume of H2 is 7.39 liters.