Calculate the volume of hydrogen that will be released when calcium interacts with

Calculate the volume of hydrogen that will be released when calcium interacts with an amount of 0.5 mol of a substance with sulfuric acid.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Ca + H2SO4 = CaSO4 + H2 ↑.

According to the reaction equation, there is 1 mole of hydrogen per mole of calcium. Substances are in quantitative ratios 1: 1,

The amount of hydrogen and calcium will be the same.

n (H2) = n (Ca) = 0.5 mol.

1 mol Ca – 1 mol H2,

0.5 mol Ca – x mol H2,

x mol H2 = (0.5 mol × 1 mol): 1 mol = 0.5 mol.

Let’s find the volume of hydrogen.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 0.5 mol × 22.4 L / mol = 11.2 L.

Answer: 11.2 liters.