Calculate the volume of hydrogen that will be released when magnesium with a mass of 64 g interacts with sulfuric acid.

Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:
Mg + H2SO4 = MgSO4 + H2;
In accordance with the coefficients of the equation, when 1 mol of magnesium is dissolved, 1 mol of gaseous hydrogen is released.
Let’s calculate the chemical amount of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.
M Mg = 24 grams / mol;
N Mg = 64/24 = 2.667 mol;
The same amount of hydrogen will be synthesized.
Let’s calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):
V H2 = 2.667 x 22.4 = 59.74 liters;