Calculate the volume of hydrogen that will be released when zinc reacts with 150

Calculate the volume of hydrogen that will be released when zinc reacts with 150 grams of 20% hydrochloric acid solution.

1. Let’s write the equation of interaction of zinc with hydrochloric acid:

Zn + 2HCl = ZnCl2 + H2 ↑;

2. find the mass of hydrogen chloride:

m (HCl) = w (HCl) * m (HCl solution) = 0.2 * 150 = 30 g;

3.Calculate the chemical amount of hydrogen chloride:

n (HCl) = m (HCl): M (HCl) = 30: 36.5 = 0.822 mol;

4.determine the amount of released hydrogen:

n (H2) = n (HCl): 2 = 0.822: 2 = 0.411 mol;

5.Calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.411 * 22.4 = 9.2 liters.

Answer: 9.2 liters.