Calculate the volume of hydrogen that will evolve when 6 mol of magnesium reacts with hydrochloric acid.

Answer: 134.4 liters.
Explanation of the solution to the problem: first, we compose the reaction equation: Mg + 2HCl = MgCl2 + H2. The reaction shows that magnesium and hydrogen are in a ratio of 1: 1, so their amounts of substance are equal, that is, the amount of hydrogen substance = the amount of magnesium substance = 6 mol. Next, we find the volume of hydrogen, for this we multiply its amount of substance by the molar volume (22.4 l / mol): V = 6 * 22.4 = 134.4 l.



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