Calculate the volume of hydrogen that will react with chlorine if 5.6 liters of hydrogen chloride is formed.

Сl2 + H2 = 2HCl
Vm = 22.4 l / mol Vm = 22.4 l / mol
V = 22.4 l V = 44.8 l
5.6 l H2 – X l Cl2
22.4 L H2 – 44.8 L Cl2
V (Cl2) = 5.6 * 44.8 / 22.4 = 11.2 L



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