Calculate the volume of hydrogen that will result from the interaction of 12 g of magnesium

Calculate the volume of hydrogen that will result from the interaction of 12 g of magnesium with an excess of hydrochloric acid.

The active element metallic magnesium, when it gets into hydrochloric acid, dissolves in it. The chemical process is described by the following equation:

Mg + 2HCl = MgCl2 + H2 ↑;

Let us determine the chemical amount of the elementary magnesium substance that has entered into this interaction.

For this purpose, we divide its mass by the weight of 1 mole of metallic magnesium (its molar weight).

M Mg = 24 grams per mole;

N Mg = 12/24 = 0.55 mol;

An equivalent amount of hydrogen gas will be synthesized.

Let’s find the volume of this synthesized hydrogen.

To do this, multiply the amount of hydrogen gas substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters). The product will give the volume of gas.

V H2 = 0.5 x 22.4 = 11.2 liters;