Calculate the volume of methane that will be required to obtain 38.5 carbon tetrachloride.

To solve, we write down the equations of the processes:

CH4 + Cl2 = CH3Cl + HCl – substitution occurs in the light, chloromethane is formed;
CH3Cl + Cl2 = CH2Cl2 + HCl – dichloromethane obtained;

CH2Cl2 + Cl2 = CHCl3 + HCl – trichloromethane formed;

CHCl3 + CL2 = CCl4 + HCl – carbon tetrachloride is released.

Calculations:
M (CCl4) = 154 g / mol;

Y (CCl4) = m / M = 38.5 / 154 = 0.25 mol;

Y (CH4) = 0.25 mol since the amount of substances is equal to 1 mol.

We find the volume of the original substance:
V (CH4) = 0.25 * 22.4 = 5.6 L

Answer: received carbon tetrachloride with a volume of 5.6 liters