To solve, we write down the equations of the processes:
CH4 + Cl2 = CH3Cl + HCl – substitution occurs in the light, chloromethane is formed;
CH3Cl + Cl2 = CH2Cl2 + HCl – dichloromethane obtained;
CH2Cl2 + Cl2 = CHCl3 + HCl – trichloromethane formed;
CHCl3 + CL2 = CCl4 + HCl – carbon tetrachloride is released.
M (CCl4) = 154 g / mol;
Y (CCl4) = m / M = 38.5 / 154 = 0.25 mol;
Y (CH4) = 0.25 mol since the amount of substances is equal to 1 mol.
We find the volume of the original substance:
V (CH4) = 0.25 * 22.4 = 5.6 L
Answer: received carbon tetrachloride with a volume of 5.6 liters
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