Calculate the volume of nitrogen that is released during the interaction of copper (II) oxide

Calculate the volume of nitrogen that is released during the interaction of copper (II) oxide with ammonia taken with a mass of 5.1 g.

3CuO + 2NH3 = 3Cu + N2 + 3H2O.

To begin with, let’s determine the mass of nitrogen based on the fact that 28 g of nitrogen is formed from 2 * 17 g of ammonia (by molar masses):

5.1 g – x g

2 * 17 g – 28 g.

We find that x = 4.2 g.

In order to determine the volume, we first find the amount of nitrogen substance:

n = m / Mr = 4.2 / 28 = 0.15 mol.

Now we can find the volume, using the fact that 1 mole of any gas at normal conditions. takes up a volume of 22.4 liters:

V = 0.15 * 22.4 = 3.36 l.