Calculate the volume of O2 that was used during the complete combustion of propene V = 4L.

Propene is an unsaturated hydrocarbon of the ethylene series. Has a gross formula C3H6. In a sufficient amount of oxygen, it burns completely to carbon dioxide and water.

2 С3H6 + 9 O2 = 6 CO2 + 6 H2O

Molar volume of gases at normal level is equal to 22.4 l / mol (according to Avogadro’s law). Because in the condition of the problem, the reaction conditions are not specified, it is taken as normal.

Let’s calculate the volume of oxygen:

4 l. propene correspond to X l. oxygen like

2 * 22.4 l / mol of propene corresponds to 9 * 22.4 l / mol of oxygen.

X = (4 * 9 * 22.4) / (2 * 22.4) = 18 liters. oxygen.

Answer: 18 liters of oxygen.