Calculate the volume of oxygen and air required to burn 10 kg of coal, the mass fraction of carbon in which is 90%.
May 31, 2021 | education
| The coal combustion reaction is described by the following chemical reaction equation:
C + O2 = CO2;
The combustion of one mole of coal requires one mole of oxygen.
Let’s determine the amount of carbon.
Pure carbon mass:
m C = 10,000 x 0.9 = 9,000 grams;
The molar mass of carbon is 12 grams / mol.
The amount of carbon substance will be:
N C = 9,000 / 12 = 750 mol;
The same number of moles of oxygen will be required.
Let’s find the volume of oxygen.
Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.
750 mol of oxygen will occupy the volume V O2 = 750 x 22.4 = 16 800 liters;
The oxygen content in the air by volume is 20.95%;
Accordingly, the required volume of air will be a volume equal to 16 800 / 0.2095 = 80 191 liters;
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.