Calculate the volume of oxygen in which 9.6 g of magnesium can completely burn.

Metallic magnesium reacts intensely with oxygen. The oxidation reaction is described by the following equation:

Mg + ½ O2 = MgO;

In this reaction, 1 oxygen atom is added to 1 magnesium atom and 1 molecule of magnesium oxide is synthesized.

Let’s determine the molar amount of magnesium.

To do this, divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 9.6 / 24 = 0.4 mol;

To burn this amount of magnesium, 2 times less chemical (molar) amount of oxygen is required.

Let’s calculate the gas volume. To do this, multiply the volume of oxygen by the volume of 1 mole, which is 22.4 liters.

V O2 = 0.4 / 2 x 22.4 = 4.48 liters;