Calculate the volume of oxygen obtained from 300 liters of air if it is known that the volume fraction of oxygen in the air is 21%?

Given: V (air) – 300 l,

ϕ (О2) – 21%,

find: V (oxygen),

V (oxygen) = (V (air) * ϕ (О2) / 100%,

V (oxygen) = (300 l * 21%) / 100% = 63 l,

Answer: V (oxygen) = 63 liters,

In nature, in air, 21% of 100% is oxygen, 78% is nitrogen and 1% is random gases.



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