Calculate the volume of oxygen reacted with 112 liters of sulfur oxide (IV)

2SO2 + O2 = 2SO3.
N sulfur oxide (IV) = 112: 22.4 = 5 mol, and the amount of oxygen is 2 times less. This means that (5: 2) * 22.4 = 56 liters of O2 enters into the reaction.



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