Calculate the volume of oxygen released as a result of the decomposition of 9 g of water.

The decomposition reaction of water is described by the following chemical reaction equation:
H2O = H2 + 1/2 O2;
From 1 mole of water, 1 mole of hydrogen and ½ mole of oxygen are synthesized.
Let’s calculate the available chemical amount of water.
M H2O = 2 + 16 = 18 grams / mol;
N H2O = 9/18 = 0.5 mol;
During this reaction, 0.5 / 2 = 0.25 mol of oxygen will be synthesized.
Let’s calculate its volume by multiplying the amount of the substance by the volume of 1 mole of the gaseous substance.
V O2 = 0.25 x 22.4 = 5.6 liters.