Calculate the volume of oxygen required for complete combustion of 1.4 mol of ethane.

Let’s execute the solution step by step:
1. Let’s compose the reaction equation:
2С2Н6 + 7О2 = 4СО2 + 6Н2О – reaction of ethane combustion, exothermic reaction is accompanied by the release of heat, carbon dioxide and water;
2. Let’s make a proportion according to the reaction equation:
1.4 mol (C2H6) – X mol (O2);
-2 mol -7 mol from here, X mol (O2) = 1.4 * 7/2 = 4.9 mol;
3. Let’s calculate the volume of oxygen according to Avogadro’s law:
V (O2) = 4.9 * 22.4 = 109.76 liters.
Answer: for the reaction of burning ethane, oxygen in a volume of 109.76 liters is required.