Calculate the volume of oxygen required for complete combustion of 112 liters of carbon monoxide (II).

The oxidation reaction of carbon monoxide is described by the following chemical reaction equation:

CO + ½ O2 = CO2;

1 mole of carbon monoxide reacts with ½ mole of oxygen. This synthesizes 1 mol of carbon dioxide.

Let’s determine the chemical amount of a substance in 112 liters of carbon monoxide.

To do this, we divide the volume of gas by the volume of 1 mole of gas.

N CO = 112 / 22.4 = 5 mol;

To oxidize such an amount of a substance, you will need 5/2 = 2.5 mol of oxygen.

Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V O2 = 2.5 x 22.4 = 56 liters;